EASY NC#133 Blind #38 Intervals
252. Meeting Rooms
📖 Problem
Given an array of meeting time intervals intervals where intervals[i] = [start_i, end_i], determine if a person could attend all meetings.
🧠 Visual Learning Aid
1 Model the input into the right structure
2 Choose the core technique and invariant
3 Execute step-by-step with a sample
4 Validate complexity and edge cases
JS/TS Refreshers
- •Array methods (`push`, `pop`, `shift`, `slice`)
- •Object/Map/Set usage patterns
- •Function parameter and return typing
Logical Thinking Concepts
- •Define invariants before coding
- •Check edge cases first (`[]`, single element, duplicates)
- •Estimate time/space before implementation
💡 Approach
- → Sort intervals by start time
- → Check if any interval overlaps with previous one
- → Overlap occurs when current start < previous end
- → Time: O(n log n), Space: O(1)
🛠️ Hints & Pitfalls
Hints
- •Sort intervals by start time
- •Check if any interval overlaps with previous one
- •Overlap occurs when current start < previous end
Common Pitfalls
- •Time: O(n log n), Space: O(1)
🧪 Test Cases
Test Case 1
Not run Input:
canAttendMeetings([[0,30],[5,10],[15,20]]); Expected:
false Test Case 2
Not run Input:
canAttendMeetings([[7,10],[2,4]]); Expected:
true Test Case 3
Not run Input:
canAttendMeetings(intervals: number[][]); Expected:
Computed from hidden reference 📝 Code Editor
📤 Output